Assuming that the tank is cylindrical: Volume = ¶*r2*h
Knowing this, the volume of the cylinder is 78.54 ft3.
1ft3 = 7.48 US liquid Gallons.
So... the tank will hold around 587.52 US liquid gallons.
To calculate the diameter of a cylindrical oil tank, you can use the formula: diameter = 2 * square root of (volume / (pi * height)), where the volume and height of the tank are known. Input these values into the formula to find the diameter.
See http://www.wolframalpha.com/input/?i=cylinder+diameter+12,+height+6
A circular tank is 12 meter in diameter and 7.5 meter in height. how much water does it hold when half full?
A 14 foot diameter tank has a volume of 154 cubic feet per foot of height and it takes 7.48 gallons per cubic foot7.48 * 154 = 1150 gallons per foot of height
A cylindrical tank will be approximately 8 feet wide and 12 feet high.
If the 9' is the diameter of the tank and the 2' is the height, then the volume is 951.78 gallons. (rounded) If the 9' is the height of the tank and the 2' is the diameter, then the volume is 211.51 gallons. (rounded)
The dimensions of the 80-gallon water tank are typically around 24 inches in diameter and 48 inches in height.
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you need to use the formula for volume which is V = πr2h, where r is the radius of the tank and h is the height.
Diameter = 5 ft therefore radius = 2.5 ft. Height = 16 ft. 7.5 gallons = 1 cubic ft. Volume of a cone = 1/3*pi*radius2*height Volume = 1/3*pi*2.52*16 = 104.7197551 cubic feet Gallons of water in the tank = 7.5*104.7197551 = 785.3981634 gallons There are 785 gallons of water in the tank correct to three significant figures.
Impossible to answer ! Even given the capacity and the height - there are still more than one answer !
The dimensions of an 80-gallon water tank can vary depending on the shape, but a common size for a cylindrical tank would be approximately 24 inches in diameter and 48 inches in height.