If the 20' is the diameter of the pool (radius 10 feet) and the depth is 48 inches (4 feet) the volume of the pool in cubic feet would be found by the formula pi x r2 x h - with pi as 3.14159, r2 as 100 and h as 4
... which gives 1256.636 cubic feet
1 cubic foot of water = 7.4805195 US gallons (or 6.2288355 Imperial gallons), so 1256.636 cubic feet would be 9,400.2901 US gallons (or 7,827.3789 Imperial gallons)
If, however, the 20' is the circumference, then the radius would be just over 3.18 feet and the formula becomes 3.14159 x 10.13 x 4
... which gives 127.297 cubic feet
That converts to 952.25 US gallons or 792.9 Imperial
If the pool is 8 feet at the deep end and 3 feet at the shallow end, the total volume will be 39,494 gallons of water.
Cant work it out without the depth and do you really mean 20 inch by 40 inch? that's tiny.
If 20' is the circumference, then the answer is 833.4 gallons.
A 100-foot round pool filled with 1.5 feet of water would be holding about 88,500 gallons.
There are 13,536 gallons in a 24 foot diameter pool that has 4 feet of water. Not true for a pool that is 4 feet in height. This would hold less than 4 feet of water.
It would fill about 91,000 residential in-ground swimming pools.
Kiloliters or gallons depending on sizeo f the pool.
All you have to do to find the volume of a swimming pool is multiply the length x width x average depth x gallons in a cubic foot (7.48). In your case it would be 38x22x5.5x7.48=34,393 gallons.
A 28-foot round pool filled with 4 feet of water would contain about 18,500 gallons.
how many ounces do of roundup do I mix with two gallons of water?
Go to http://www.havuz.org/pool-calculators.htm