2,8 moles of calcium carbonate have 240,208 g.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
No. of moles=wt. of substance/molecular wt. hence, wt. of substance= 2.38*100=238
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
1,5 moles of potassium carbonate have 276,41 g.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
42,5 grams calcium is equivalent to 1,06 moles.
120 grams of calcium contain 2,994 moles.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
No. of moles=wt. of substance/molecular wt. hence, wt. of substance= 2.38*100=238
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
234 grams :)
1,5 moles of potassium carbonate have 276,41 g.
7,68 grams of calcium nitride is equal to 0,052 moles.
3 moles of calcium is equivalent to 120,234 g.