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2,8 moles of calcium carbonate have 240,208 g.

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Q: How many grams are in 2.8 moles of calcium carbonate?
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How many moles of calcium carbonate are in 1.719 grams?

Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.


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How many moles of calcium is 126g of ca?

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