Easy...the Periodic Table gives the average mole weight of each element averaged out over all it's naturally occurring, if any, isotopes, i.e.,
K is 39.09
Br is 79.9
Add them up and it's (to three significant figures):
So KBr is 119 g/mole
[Molar mass of 119 g/mol KBr] * 3 mol KBr = 357 grams for 3 moles KBr
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
7.56 X 1011 atoms of oxygen (1 mole O/6.022 X 1023)(1 mole V2O3/3 mole O)(149.88 grams/1 mole V2O3) = 6.27 X 10 -11 grams vanadium oxide ===========================
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
357
357
150 grams NH3 (1 mole NH3/17.034 grams)(3 mole H/1 mole NH3)(1.008 grams/1 mole H)= 26.6 grams hydrogen=================17 g of ammonia has 3 g of hydrogen.So 150 g of ammonia will have 26.5 g of hydrogen
60 g
3 moles of ammonia is 51grams. One mole is 17 grams.
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
7.56 X 1011 atoms of oxygen (1 mole O/6.022 X 1023)(1 mole V2O3/3 mole O)(149.88 grams/1 mole V2O3) = 6.27 X 10 -11 grams vanadium oxide ===========================
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5