The nitrogen iodide is NI3.
106.7 grams
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
107.5 g N2I6
Quite a few! 8.2 X 10^22 atoms of N2I6 (1 mole N2I6/6.022 X 10^23)(789.42 grams/1 mole N2I6) = 107 grams of N2I6 (Would have been peanuts without all that iodine! )