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2NaCl + H2SO4 ----> 2HCl + Na2SO4

*molar mass of H2SO4 is 98.09g

*molar mass of NaCl is 58.44g

*molar mass HCl is is 36.46g

Moles NaCl = 150 g / 58.44 = 2.56

The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant

We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g

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Q: How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
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How many grams of HCl can be prepared from 2.00 mol H2SO4 and 150 g NaCl?

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