2NaCl + H2SO4 ----> 2HCl + Na2SO4
*molar mass of H2SO4 is 98.09g
*molar mass of NaCl is 58.44g
*molar mass HCl is is 36.46g
Moles NaCl = 150 g / 58.44 = 2.56
The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant
We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
Cf. Related questions on NaCl
As the molar mass of NaCl is 58.5 g/mol, 1.6 moles weight is 93.6 grams.
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
Try asking Google
NaCl doesn't neutralize sulfuric acid.
Infinite because Sodium Chloride is neutral and will not neutralize sulfuric acid.
96.75 grams of NaCl
The answer is 8 g NaCl.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
100% pure H2SO4 doesn't exist
1 mole H2SO4 = 98.078g H2SO4
About 245 grams.
49.03924
Balanced equation. H2SO4 + 2NaOH >> Na2SO4 + 2H2O 10 grams NaOH (1mol NaOH/39.998g )(1mol H2SO4/2mol NaOH )(98.086g H2SO4/1molH2SO4 ) = 12.26 grams of H2SO4
100ml / 1000 = 0.1mol *1M = divide by 1000 moles = mass / molecular mass mass = mole x molecular mass of nacl mass = 0.1 x 58.5 mass = 5.85 answer is 5.85 grams