How many grams of magnesium and oxygen react to form 20 g of magnesium oxide?

Answer 1

Balanced Formula:

2Mg + O2 --> 2MgO

Mole ratio:

2 : 1 : 2

Givens:

.486 g oxygen

.738 g magnesium

24.3 g = Atomic Mass of magnesium

16.0 g = atomic mass of oxygen

40.3 g = molecular mass of magnesium oxide

Find the amount (in moles) of Magnesium oxide that oneelement will make:

(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO

(.783 g Mg) / (24.3 g Mg) = .0322 moles MgO

There is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.

Convert moles of MgO produced with the amount of oxygen to grams:

.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced

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You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.

Source: (e2020)

Answer 2

One mole of magnesium reacts with one mole of oxygen (1/2 moles of molecular oxygen) to produce MgO. 40.0 g of O2 molecules is 2.5 moles of oxygen atoms (1.25 moles of oxygen molecules). Therefore it reacts with 2.5 moles of Mg which is equivalent to 60.0 g.

Answer 3

I believe it is 0.114g

I just had the same question in my chem homework and this was the answer I got.

UPDATE

It definitely is 0.114g. I just submitted my homework and got the question correct. I would post my equations on here but I think I arrived at the answer in a very unconventional way lol.

Answer 4

Magnesium: 12,06 g
Oxygen: 15,88 g

Answer 5

1.269