Elements and Compounds

Salt (Sodium Chloride)

Top Answer

It depends how strong a solution you want to make.

The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre.

For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.

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058 milligrams of NaCl are needed.

If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.

Use liters to match other units. So. 100 ml = 0.1 liters Molarity = moles of solute/ volume ( liters in this case ) of solution 1 M NaCl = moles NaCl/0.1 liters = 0.1 moles NaCl (58.44 grams/1 mole NaCl) = 5.844 grams of NaCl needed to make solution.

The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl

You need 12,5 sodium chloride.

The concentration is not specified in your question !

Moles of NaCl=6*3=18mol Mass needed=[35.5+23]*18=1053g

The mass of NaCl is 14,61 g.

[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M

It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.

The volume is 79,85 mL.

Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl

how many grams of calcium nitrate are needed to make a 500ml volume of a .5 molar solution

HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.

58 grams of NaCl in cylinder measure water to 100ml

0.5 M means 0.5 moles per liter. so it depends on how many liters of solution that you need.Suppose you want to make 1 liter of solution, then you need 0.5 moles of NaClFrom the webelements.com Periodic Table:Atomic mass of Sodium (Na) = 22.990 & Atomic Mass of Chlorine (Cl) = 35.453So 1 mole of NaCl = (22.990 + 35.453) grams = 58.443 gramsBased on the 1 liter, we want to add 0.5 moles: (58.443 grams/mole)*(0.5 mole) = 29.2215 g (to make 1 liter of 0.5 M solution)

The answer is 7,5g.

You need 58,44 g NaCl for 1 L water to make a molar solution.

2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.

Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M

If we add 1 L of water to 1 L of 2 M NaCl solution will give 2 L of 1 M NaCl solution

The answer is 3,211 g.

You are probably referring to a solution of NaCl and water, in which case NaCl would be the solute. Water would be the solvent, and combined they make the whole solution.

I suppose that this solution doesn't exist.

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