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How many grams of chlorine gas are needed to make 117 grams of sodium chloride?
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∙ 11y ago
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∙ 11y ago
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How many grams of sodium chloride are needed to prepare 600 ml of a 0.9 percent saline solution?
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
There is 46 grams of sodium and 23 grams of Chlorine How many gram of sodium chloride can be produced?
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams
How many grams of sodium are needed to produce 5.3 moles of sodium chloride?
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
How many grams of salt is 80 mmol sodium?
1 mmol sodium = 23 mg sodium chloride 80 mmol sodium chloride = 80 x 23= 1840 mg sodium chloride
If 2 moles of sodium carbonate are used in the reaction how many grams of sodium chloride will be formed?
234 grams
How many grams of Chlorine are in 7 grams of Sodium Chloride?
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
In a reaction between sodium and chlorine 10 grams of sodium is needed to prepare 35 grams of sodium chloride How many grams of chlorine is needed for this reaction?
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
If 75 grams of sodium reacts with 25 grams of chlorine how many grams of salt will be produced?
75 g sodium chloride contain 29,75 g sodium.
Given That Sodium Chloride Is 39.0 Sodium By Mass How Many Grams Of Sodium Chloride Are Needed To Have 750mg Of Na Present?
The answer is 1,105 g.
What mass of sodium chloride is formed if 22.99 grams of sodium combines with 35.54 grams of chlorine?
You have one mole sodium and one mole chlorine so one mole NaCl will be formed that weight as (23+35.5)=58.5 g
How many grams of sodium metal are needed to make 29.3 grams of sodium chloride?
It will be 11.5 gm od Na metal
How many grams of sodium chloride would you need to make a 5.0m salt solution?
The sodium chloride mass needed is 292,2 g
How many grams of HCl are needed to make 21.5 grams of Na2SO4?
Sodium sulfate is not prepared from hydrogen chloride.
How many grams of sodium chloride are needed to prepare 600 ml of a 0.9 percent saline solution?
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
How many gram of chlorine are need to combined with 23gram of sodium to make 58.5gram of sodium chloride?
From the law of conservation of mass: 58.5 - 23 = 35.5 grams of chlorine required. Interestingly, 23 and 35.5 are approximations to the gram atomic masses of sodium and chlorine respectively.
Why is the scientific name NaCl?
Sodium chloride got its name because it's chemical formula is NaCl; 1 sodium atom and one chlorine atom. When a chlorine atom is part of an ionic compound, it's end is changed from -ine to -ide.
How many grams of sodium chloride would be made if 46 grams of sodium completely reacted with 70 grams of chlorde?
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)
