go in your basment, grab a robe , and hang yourselfs
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
417.2 grams FeCrO4 (1 mole FeCrO4/171.85 grams) = 2.428 moles iron (II) chromate =========================( also known as ferrous chromate )
620 grams mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
To calculate the number of moles from grams, you must divide by the substance's molar mass
1,25 g of anhydrous iron(III) nitrate = 0,005 moles
The mass of 4 moles of iron is 224 grams
388.grams Fe divided by mass of Fe 388.2g/55.85= 6.95moles of Fe
This cannot be answered because it is essential to know what element you're dealing with here. 8.2 grams of iron will contain considerably less atoms than 8.2 of hydrogen. Therefore, the number of moles in 8.2 grams of iron will differ from the number of moles in 8.2 grams of hydrogen.
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
Use the equation; mass=moles*gramformulamass or m=n*gfm m=2*55.8 = 111.6g in two moles of Iron gfm or the molecular mass of a compound can be found by adding the Relative atomic masses of each element in the compound together. For example - Carbon dioxide CO2 The formula contains 1 Carbon atom and 2 Oxygen atoms (RAMs should be found in a datasheet/book or provided in the question. RAM = relative atomic mass) RAM Carbon = 12 RAM Oxygen = 16 gfm of CO2 = 12 + 32 = 44 or 1mole of CO2 = 44g