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One mole has amass of 16g.There are 6.428mol.Its mass is 102.85g

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Q: How many grams of methane gas CH4 are contained in a volume of 144 liters at STP?
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The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol. Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters. But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved. Carbon = 12.0 grams Hydrogen = 1.01 grams × 4 atoms = 4.04 grams ------------------------------------------------------------- Methane = 16.04 grams To convert grams to moles: Grams of substance ÷ Molar mass (in grams) = Moles of substance 2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4 Now we follow through with our proportion: 22.4 L/1 mol = x L/.180 mol x = 4.03 L 2.88 grams of methane occupies 4.03 liters at STP


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