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Answered 2017-12-20 11:44:59

You have2KClO3 ==> 2KCl + 3O2 as the balanced equation

25 g KClO3 x 1 mole/123 g = 0.20 moles

moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed

grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed

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