How many grams of sodium are needed to produce 5.3 moles of sodium chloride?
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio
mass = moles X molar mass
m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
In a reaction between sodium and chlorine 10 grams of sodium is needed to prepare 35 grams of sodium chloride How many grams of chlorine is needed for this reaction?
One mol of sodium chloride has a mass of 58.443 grams. This is calculated by adding the molecular weight of each component of sodium chloride. Sodium chloride has a formula of NaCl. This means that one molecule of sodium chloride has one sodium atom and one chlorine atom. The molecular weight of the sodium portion of the molecule is 22.9898 grams/mol and the molecular weight of the chlorine part of the molecule is 35.4532 grams/mol…
To combine equal numbers of sodium and chloride atoms in a flask how much Chloride would you have to add if you added 23 Grams of sodium?
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams). Thus 10 moles would weigh 10x58.5 grams = 585 grams. The answer is 585 grams.
The formula of sodium chloride is NaCl; therefore, the gram formula mass of sodium chloride is the sum of the gram atomic masses of sodium and chloride, or 58.443, to the justified number of significant digits. The number of gram formula masses in 23.376 grams is therefore 23.376/58.443 or 0.399998, to the justified number of significant digits.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If…