This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles.
Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
Green
sodium acetate and water are formed.
sodium nitrate
The Result is Imran.
Nothing
Green
Sodium react with water forming a base - sodium hydroxide - and releasing hydrogen. Add an acid for neutralization.
No, adding solid sodium hydroxide to neutralize hydrochloric acid (HCl) would not cause sodium chloride to redissolve. The reaction between sodium hydroxide and hydrochloric acid forms water and sodium chloride, which remains in its dissolved form. The addition of solid sodium hydroxide would simply further neutralize the acid and increase the concentration of the resulting sodium chloride solution.
There are times when bacteria, acidify an infected site, therefore adding sodium hydroxide will neutralize the region for a basic site.
how much sodium hydroxide in grams must be added to seawater to precipitate 86.9mg of magnesium present?
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
No. Sodium hydroxide releases hydroxide ions, which actually take protons out of the solution. This qualifies sodium hydroxide as a base.
Metallic copper does not react with sodium hydroxide. But if sodium hydroxide is added into a solution of copper ions, it would form Copper(II) Hydroxide. It is a precipitate which is insoluble in water.
See this link.
sodium hydroxide solution
A base - sodium hydroxide.
sodium acetate and water are formed.