C7H5N3O6
Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters )
0.100 M C7H5N3O6 = X moles/0.25 L
= 0.025 moles
-------------------------now,
0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6)
= 5.68 grams TNT
====================a good firecracker!
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
25 mL
35.38g
The needed mass is 35,549 g.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
25 mL
105 g
10
35.38g
25
The needed mass is 35,549 g.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
1.17 grams :)
Sodium chloride may be used as standard (for example to prepare sodium solutions with known concentration) because is a stable compound.
4 moles or 160 g NaOH is required for one litre solution.
2.07g