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2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2

300 grams O2 x 1 mole O2/32 g = 9.375 moles O2

Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 moles

grams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)

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Q: How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
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