Answers:
- 9,033.10 ex. 23 calcium atoms
- 18,066.10 ex.23 chlorine atoms
there is Ca raise to power 2+
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
1.46 Moles CaCl2 (6.022 X 10^23/1 mole CaCl2) = 8.79 X 10^23 molecules of calcium chloride
The chemical formula for calcium chloride is CaCl2, and its formula weight is 110.99. The formula shows that each formula weight of calcium chloride contains one mole of calcium ions. In 166.5 grams, there are 166.5/110.99 or 1.500 formula weights of calcium chloride and the same number of moles of calcium ions.
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
1.46 moles CaCl2 (6.022 X 1023/1 mole CaCl2) = 8.79 X 1023 molecules of calcium chloride ================================
1.46 Moles CaCl2 (6.022 X 10^23/1 mole CaCl2) = 8.79 X 10^23 molecules of calcium chloride
If grams/molar mass=moles, then first the molar mass of the compound must be found. CaCl2 has a molar mass of 110.984. Divide the number of grams, 15.5, by 110.984, and you get the number of moles. Now, seeing as calcium is not diatomic like oxygen or chlorine, there needs to be no conversion between the number of moles of calcium in the compound and the number of moles of calcium outside of the compound. atoms, the number of calcium atoms in the compound divided by one mole of the compound will give us the ratio. Conveniently enough, that ratio is one calcium atom per molecule of calcium chloride, meaning that for every one mole of calcium chloride, 1 mole of pure calcium can be extracted. So once you find the number of mole of CaCl2, that is the number of moles of calcium as well. This may be a little difficult to grasp, but I'm sure that your teacher, if you're a student, will be able to explain why rather well.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
The chemical formula for calcium chloride is CaCl2, and its formula weight is 110.99. The formula shows that each formula weight of calcium chloride contains one mole of calcium ions. In 166.5 grams, there are 166.5/110.99 or 1.500 formula weights of calcium chloride and the same number of moles of calcium ions.
Calcium is one element, and chloride is the element to make up the structure of calcium chloride, which is CaCl2.By the molecular formula, we see that there are two chloride atoms and one calcium atom in one molecule of calcium chloride. This means that there are two times as many atoms of chloride than calcium in the structure.If nothing else is stated, the number of moles is always equal to 1 for any element. One mole is equal to 6.022 x 1023 atoms. There are thus:1×(6.022 x 1023)=6.022 x 1023 atoms of calciumand2×(6.022 x 1023)≈1.2 x 1024 atoms of chloride
You get 1 Mole Of Calcium Carbonate "Chalk", along with 2 Moles of Sodium Chloride "Salt" Na2CO3 + CaCl2 -------------> CaCO3 + 2NaCl
The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
The total number of atoms in 3.5 moles of calcium is 21,0774929995.10e23.
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.