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q = mass * specific heat * change in temperature

q = (50.0 grams H2O)(4.180 J/g*C)(60o C - 70o C)

= - 2090 joules heat energy released

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11y ago
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11y ago

a change from liquid to solid or solid to liquid will require the use of the formula of

Heat of Fusion , q=mHf where m is the mass and Hf = 334J/g, this is standard so you wont have to look for how it came about.In this case the m=5.00g so:

q = m Hf

q=(5.00g)(334 J/g) , you notice the grams will cancel out.

q = 1670 J.

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9y ago

The specific heat of water is 4.179 J/g 0C. Using the equation Q = mc(change in T), the heat given off by this temperature change can be calculated. This is approximately 1.0 kJ.

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13y ago

Q=mcθ where;

m=Mass

c=Specific heat capacity of water (4200 JKg-1K-1)

θ=Change in temperature

Q= 0.005 x 4200 x (75-25)

Q= 1050J

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11y ago

q=m c (Tf-Ti)

= 225g (4.18j/g C) (75C - 42C)

=answer

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13y ago

4.184 J/g/K so 4.184 x 5 x (85-25) = 1255.2 Joules

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13y ago

4.184 J/g/K = 4.184 x 75 x (70-20) = 15690 Joules

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12y ago

q = m*specific heat*change in temp.

q = (76 grams H2O)(4.180 J/gC)(80 C - 20 C)

= 1.9 X 104 Joules

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7y ago

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Q: How many joules of energy are required to raise the temperature of 75.0 grams of water from 20.0oC to 70.0oC?
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