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In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state.

The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice.

Joules needed to melt the ice = 333.55 J/g x 40 g = 13342 J

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12y ago
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11y ago

c. 1.26 grams

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11y ago

About 13,340 Joules.

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11y ago

About 5,525 Joules.

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11y ago

.186g

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Q: How many joules of heat are requied to melt 40 g of ice at 0 C?
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In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. 1 kg = 1000g 40kg x (1000g/1kg) = 40,000g Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000 J or 1.3342 x 107 J


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