How many joules of heat are required to melt 40 kg of ice at 0 dg C?
In order to answer this question, you need the enthalpy of
fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of
fusion is the amount of heat that must be absorbed or lost in order
to change physical state.
The number of Joules required to melt the ice = enthalpy of
fusion of ice x mass of ice.
1 kg = 1000g
40kg x (1000g/1kg) = 40,000g
Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000
1.3342 x 107 J