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What is the number of kilograms of solvent in a 0.70 molal solution containing 5.0 grams of solute (molar mass of solute 30 g)?
Wiki User
∙ 6y ago
molarity = moles of solute/ kilogram of solvent
0.30=13/x
0.30x=13
x=13/0.30
x=4.333333333333333333
Wiki User
∙ 12y ago
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Formula for molality?
== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==
What solution has the maximum number of grams of solute that can be dissolved?
The maximum number of grams of solute that can be dissolved in a given solvent is dependent on factors such as temperature, pressure, and the specific solute-solvent system. This maximum amount is known as the solubility limit of the solute in that particular solvent.
When double replacement reactions in aqueous solution produce water the number of solvent particles decrease?
false
How do you solve molality?
To solve boiling point elevation problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is 0.52 K·kg/mol (or 0.52 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a boiling point elevation is known and is equal to 0.52 °C·kg/mol (or 0.52 °C molal-1). Notice it is positive -- for freezing point depression problems, the value of Kf is negative.The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!See the Web Links and Related Questions for more information!
What is the meaning of the term Concentration of a solution?
In general the amount of a solute (the smaller component) in a solvent (the larger component). The higher the concentration the more solute relative to solvent. This can be expressed many ways such as molarity (moles per liter), molalitity (moles per kilogram of solvent), weight percent, volume percent, etc.
Formula for molality?
== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==
What is the molality of a substance?
Molality is the number of moles of a solute divided by the weight of the solvent in kilograms.
What is molality of a solution?
It is the number of moles of solute in 1 kg of solvent.
What solution has the maximum number of grams of solute that can be dissolved?
The maximum number of grams of solute that can be dissolved in a given solvent is dependent on factors such as temperature, pressure, and the specific solute-solvent system. This maximum amount is known as the solubility limit of the solute in that particular solvent.
What is the molality of solution?
The number of moles of a solute per kilogram of solvent. (Apex)
What is the corrosive solution containing the element with the atomic number 8?
Oxyacid
Corrosive solution containing element with atomic number 8?
Oxyacid
What is the Corrosive solution containing the element with atomic number 8?
oxyacid
When double replacement reactions in aqueous solution produce water the number of solvent particles decrease?
false
What is the different between molality and molarity?
The difference is in the denominators.Molarity (M) - the number of moles of solute divided by the number of liters of solution.Molality(m) - the number of moles of solute divided by the number of kilograms of solvent.
What is the solution's freezing point depression?
To solve freezing point depression problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is -1.858 K·kg/mol (or -1.858 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a freezing point depression is known and is equal to -1.858 °C·kg/mol (or -1.858 °C molal-1)The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!
How do you solve molality?
To solve boiling point elevation problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is 0.52 K·kg/mol (or 0.52 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a boiling point elevation is known and is equal to 0.52 °C·kg/mol (or 0.52 °C molal-1). Notice it is positive -- for freezing point depression problems, the value of Kf is negative.The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!See the Web Links and Related Questions for more information!
