2 m
M=moles/L
0.2=0.4/x
0.2x=0.4
x= 2
which means 2 liters
.5 moles = .5 moles per litre.
2 moles / .5 moles per litre = 4 litres
RMM OF NaOH= 23+16+1= 40g/mol # mol of NaOH= 42/40= 1.05 mol Concentration= mol/dm 1.05 mol=2.3dm3 X mol = 1 dm3 X=(1.05*1)/2.3 X=.04565M
Balanced Equation. NaOH + HNO3 >> NaNO3 + H2O Now, Molarity = moles of solute/liters of solution 0.800M HNO3 + mol/2.50L mol of HNO3 = 2 2mol HNO3 (1mol NaOH/1molHNO3 )(39.998g NaOH/1mol NaOH ) = 79.996 grams
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M
Convert the 200 mol of water to kilograms of NaCl
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
This molarity is 3 mol/L.
0.5M apex
-1602 kJ
Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)
RMM OF NaOH= 23+16+1= 40g/mol # mol of NaOH= 42/40= 1.05 mol Concentration= mol/dm 1.05 mol=2.3dm3 X mol = 1 dm3 X=(1.05*1)/2.3 X=.04565M
1,574 mol/L NaCl
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
The molarity is 2 mol/L.
Balanced Equation. NaOH + HNO3 >> NaNO3 + H2O Now, Molarity = moles of solute/liters of solution 0.800M HNO3 + mol/2.50L mol of HNO3 = 2 2mol HNO3 (1mol NaOH/1molHNO3 )(39.998g NaOH/1mol NaOH ) = 79.996 grams
[4.00 (g) / 40.0 (g/mol)] / 2.00 (L) = [0.100 (mol)] / 2.00 (L) = 0.0500 mol/L