55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)
In the liquid form, it works out to just under 62 milliliters.
Answer: 16 g of oxygen and 2 g of hydrogen.
The atomic mass of Oxygen is about 16. Water contains 1 oxygen atom. The Atomic mass of hydrogen is about 1. Water contains two hydrogen atoms. Therefore in water by mass the proportion of hydrogen to oxygen is 2/16 or 1/8 This means that in 100 grams of water there is 12.5 grams of hydrogen and 87.5 grams of Oxygen.
43.2 grams of water
When 9.00 g c6h12o6 burns with excess oxygen 13.2 grams of CO2 will be made.
If 14,8 grams of hydrogen reacted with 34,8 grams of oxygen the mass of water obtained is 39,15 g.
The reaction is 2H2 + O2-> 2H2O So, both the molar and volume ratios would be 2 moles(liters) of hydrogen to every mole(liter) of oxygen. By weight, the ratio would be about 8 grams of oxygen to every gram of hydrogen
The percentage of oxygen is 54,84 %.
36 grams of water
This question needs additional information to enable me correctly answer it.
Each water molecule contains exactly 2 hydrogen atoms and one oxygen atom. The gram atomic mass of oxygen is 15.9994, and the gram atomic mass of hydrogen is 1.008. Therefore, the ratio by mass of water to the oxygen contained in the water is [(2)(1.008) + 15.9994]/15.9994 or about 1.126. 20 grams of oxygen will form 22.52 grams of water,of which2.5 grams, to the justified number of significant digits,will be hydrogen.
It is not measured in grams but PPM because it is a gas.
2 grams of hydrogen gives 1 mole of hydrogen gas 16 grams of oxygen gives 1/2 mole of oxygen gas. 1H2+1/2 O2--->1H2O 1 mole of water=1x(2+16) =18g
The formula of water is H2O, showing that two atoms of hydrogen are required for each atom of oxygen in water. The gram atomic mass for hydrogen is 1.008, and the gram atomic mass for oxygen is 15.9994. Therefore 4.00 grams of hydrogen constitutes 4.00/1.008 or 3.97 gram atomic masses of hydrogen, while 4.00 grams of oxygen constitutes only 4.00/15.9994 or 0.250 gram atomic masses of oxygen. Oxygen is therefore the limiting element in this reaction, and only 0.500 gram atomic masses of hydrogen can be reacted with the available amount of oxygen. The grams of water formed will be [4.00 + (0.500)(1.008)] or a total of 4.50 grams of water, to the justified number of significant digits.
22,4liters ofany gas will weigh (in gram) the same amount as its molecular weight, (at 1 atmosphere and at 0degrees celsius) Therefore 22,4l of Oxygen will weigh 32 grams,and 1 kg oxygen will be 700 liters
43.2 grams of water
67.5 grams of H2O
lets see. H20 you have 2.016 grams of hydrogen here to 16.0 grams oxygen 2.016/16.0 X 100 = 12.6% hydrogen by mass H2O2 you have the same 2.016 grams hydrogen here, but you have 32.0 grams oxygen in this molecule 2.016/32.0 X 100 = 6.3% so H2O has the higher percent by mass of hydrogen
This oxide may be CdO.
This question is not specific and can therefore not be answered accurately.