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You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below.

By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.

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11y ago
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13y ago

M1V1=M2V2

.5M x ?mL = .25M X 500mL

Rearrange it and you get ?mL = (.25M x 500mL) / .5

Which equals 250mL needed of the .5M NaCl.

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13y ago

Try boiling off 75% of the water...

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Q: Given a stock solution of 0.5 M NaCl describe how you would prepare 100ml of 2M of the solution of NaCl?
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