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nswer:12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution


Let x = 50% acid solution

y = 20% acid solution

Equations:

x + y = 36mL ----equation (1)

0.5x + 0.2y = 0.3 * 36

0.5x + 0.2y = 10.8

multiplying by 10

5x + 2y = 108 ----equation (2)

eliminating equations (1) and (2)

-2(x + y = 36)-2

-2x -2y = -72

5x +2y = 108

=========

3x = 36

x=12

substitute x=12 to equation (1)

12 + y = 36

y = 36 - 12

y = 24

thus 12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution




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Q: How many milliliters of a 50 percent acid solution and how many milliliters of a 20 percent acid solution must be mixed to produce 36 mL of a 30 percent acid solution?
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