A
nswer:12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution
Let x = 50% acid solution
y = 20% acid solutionEquations:
x + y = 36mL ----equation (1)
0.5x + 0.2y = 0.3 * 36
0.5x + 0.2y = 10.8
multiplying by 10
5x + 2y = 108 ----equation (2)
eliminating equations (1) and (2)
-2(x + y = 36)-2
-2x -2y = -72
5x +2y = 108
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3x = 36
x=12
substitute x=12 to equation (1)
12 + y = 36
y = 36 - 12
y = 24
thus 12mL of 50% solution and 24mL of 20% solution must be mixed to produce 36mL of a 30% acid solution
10
210Type your answer here...
25 gallons
120liters
1.5 pints
133.33
Let v be the capacity in milliliters of the 75% solution required then (90 - v) is the required capacity of the 84% solution needed. 75/100v + 84/100(90 - v) = 77/100 x 90 75v + 84(90 - v) = 77 x 90 75v + 7560 - 84v = 6930 9v = 7560 - 6930 = 630 v = 70 : therefore (90 - v) = 20 The mixed solution requires 70ml of the 75% solution and 20ml of the 84% solution to create 90ml of 77% solution.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
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10
210Type your answer here...
10 gallons..
25 gallons
120liters
1.5 pints
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120