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A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
Wiki User
∙ 14y ago
Make sure that the equation is balanced.
NaOH + HNO3 > > NaNO3 + H2O ( all one to one )
15.0 grams NaOH (1mol NaOH=39.998g) (1mol HNO3/1mol NaOH)
= 0.375 moles of HNO3
Molarity = mols solute/volume solution
2.00M HNO3 = 0.375 mols/X volume
= 0.188 Liters or, 188 milliliters.
Wiki User
∙ 13y ago
Wiki User
∙ 14y ago80.0 g
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A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
97.8 - 98.2 98 worked for me
What is the molarity of an HCL solution if 125ml is neutralized in a titration by 76.0ml of 1.22m KOH?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200M nitric acid solution?
262 - 266
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200 M nitric acid solution?
262 - 266
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
97.8 - 98.2 98 worked for me
How many liters of 5.00 M hydrochloric acid solution are needed to completely neutralize the magnesium hydroxide?
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How many liters of 5.00 M hydrochloric acid solution are needed to completely neutralize the strontium hydroxide?
0.0932 L
How many grams of solid barium hydroxide are needed to exactly neutralize 14.7 mL of a 0.597 M perchloric acid solution?
How many grams of KHP are needed to exactly neutralize 36.7 mL of a 0.328 M barium hydroxidesolution
What is the molarity of an HCL solution if 125ml is neutralized in a titration by 76.0ml of 1.22m KOH?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
How may milliliters of 0.200 moles Sodium Hydroxide are required to completely neutralize 5.00 milliliters of 0.100 moles Phosphoric acid?
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
