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How many ml of 6.00 M HCl are needed to prepare 1500 ml of 0.200 M HCl solution?
Wiki User
∙ 10y ago
There is an easy way to calculate this, the formula is c1*V1= c2*V2 where c1 = stock concentration (in this case 8 M); c2 = wanted concentration ( 2 M); V1= how much volume of solution 1 (stock solution, in this case 8 M HCl) is needed; V2= desired volume of solution 2 (in this case 2 M HCl). To determine how much 8 M HCl you need you use a modification of the formula above. V1= (c2*V2 ) / c1 = (2 M * 0,150 l )/ 8 M = 0,0375 l So to make 150 ml 2 M hydrochloric acid you need to dissolve 37,5 ml of 8 M HCl in 112,5 ml H2O. Remember to always put acids into water and not the other way around!
Wiki User
∙ 14y ago
Wiki User
∙ 10y ago50ml
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