One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.
So you just multiply 0.03542 moles with 6.02 × 1023 and get 2.13 × 1022
Just multiply by avagadro number.Avagadro number is 6.022 × 10^23
Multiply it by avagadro number.So you can get 0.015055
6 molecules of oxygen are needed to react with 3 methane molecules as one molecule of oxygen ( O2) are needed for methane gas.
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
4.66715966 × 1024
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
6 molecules of oxygen are needed to react with 3 methane molecules as one molecule of oxygen ( O2) are needed for methane gas.
To find moles, simply divide the number of representative particles (in this case, molecules of methane) by Avogadro's number (6.02x1023.)2.45x1023/6.02x1023 = approx. 0.41 moles (the exponents cancel out.)
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
First divide 6.25 by 16.Then moltiply by avagadro constant 6.02 × 10 23
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
How many molecules are in 30 liters of methane (CH4) at STP
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
4.66715966 × 1024
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.