To find the answer do the following:
(1) Convert mg to g by dividing by 1000 (1g = 1000mg).
(2) Divide the number of grams by 32 (there are 32g of O2 in one mole of O2).
(3) The answer is 0.0000078 = 7.8E-6 mole. Step three may not be intuitive. If you divide an amount of a substance in grams by the substance's atomic weight, that tells you how many moles of that substance you have.
Always there are 6.02*1023 particles in ONE mole:
(very much the same as: How many WhatSoEver in a dozen (12) or gross (144)
In 0.25 moles = 0.25*6.02*1023 = 1.5*1023molecules O2
Assuming standard temperature and pressure...,
PV = nRT
(1 atm)(X V) = (0.25 moles O2)(0.08206 L*atm/mol*K)(298.15 K)
= 6.1 Liters oxygen in volume
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0.25 mole x 6.022x1023 atoms/mole = 1.5055x1023 atoms
Divide 25 by molecular mass 16.Then multiply by avagadro constant 6.02 × 10 23
How many molecules in CH4?
5 g
10 moles of oxygen atoms or 5 moles of oxygen molecules.
There is 25.0 moles Oxygen
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
This volume is 6,197 399 5 at 25 0C.
The amount of oxygen is 0,067 moles.
The volume is 67,395 L (25 0C and 1 at).
38 L
38 L
10 moles of oxygen atoms or 5 moles of oxygen molecules.
3,7 moles of C8H11NO2 have 3,7 moles of oxygen (O2).
3 moles of oxygen are obtained from 2 moles of potassium chlorate.M of KClO3 is 122,55 g, M of O2 is 32, density of oxygen is 1,429 g/L.
16 grams of oxygen how many moles is 0,5 moles.
Yes volume is directly related to moles
Since oxygen is diatomic it requires 2 moles of oxygen.
The nunber of moles of oxygen is 2,5.