It's not entirely clear what you're trying to ask.
6.023x 1023 molecules.
Also known as Avagadro's Number
2 moles or roughly 12E23 atoms.
1 mol is equal to 6.02214179(30)×1023 molecules of the substance. The molecular weight is how much grams these molecules (6.02214179(30)×1023) weigh. Meaning g/mol.
H2o2
h2o2
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
1 mol is equal to 6.02214179(30)×1023 molecules of the substance. The molecular weight is how much grams these molecules (6.02214179(30)×1023) weigh. Meaning g/mol.
H2o2
h2o2
4.51 g x 1 mol x 6.022 x 1023 molecules = 9.95 x 1021 molecules .............273 g ............... 1 mol
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
5.418E23 molecules
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
Hydrochloric Acid is a Compound. Molecular formula: HCl Molecular Mass: 36.46 g/mol
Nh2cl
253.81 g mol-1
The molecular weight(M) of chalk(CaCO3) = (40+12+48)g/mol =100g/mol and teaspoon (m)= 4.93g We know, n=m/M So, n= (4.93/100) mol = .0493 mol To find out number of molecules we use, N= n x NA equation. N= .0493 mol x 6.02 x 1023 molecules/mol =2.968 x 1022 molecules Therefore, there are 2.968 x 1022 molecules in a teaspoon of chalk.