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What number of moles of O2 is required to react with 3.6 mol SO2 in the following reaction 2S02 plus O2 2SO3?
Wiki User
∙ 6y ago
2SO2 + O2 ==> 2SO3
moles of SO2 present = 98.6 g x 1 mole/64 g = 1.54 moles
moles O2 needed = 1/2 (1.54 moles) = 0.770 moles O2 needed(b/c mole ratio of O2:SO2 is 1:2)
Wiki User
∙ 7y ago
Wiki User
∙ 13y agoAssuming the questioner is intending to produce SO2:
5.48/32.065=0.17 mol
Hence 0.17 x NA = 1.029x1023 molecules of O2 are needed.
Wiki User
∙ 12y agoSO3 is Molecular Weight 80. 40.0g is thus 0.5 moles so there are 3 x 0.5 x 6.022 x 1023 atoms of oxygen = 9.033 x 1023 oxygen atoms in 40.0 g of SO3.
Wiki User
∙ 6y ago1,8 of moles of O2 are required.
Anonymous
4.63x10^23
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