The answer is 0,0719 mol.
Argon (Ar) is a noble gas and exists as a monatomic element.
Atomic Mass of Ar = 39.9
Amount of Ar = 11.6/39.9 = 0.291mol
There are 0.291 moles of argon in a 11.6g sample.
90.0g x 1 mol Ar/39.948 g Ar = 2.25 mol Ar
You multiply the grams you have (90.0g) by the ratio of one mole of Ar and its corresponding molar mass as found on the periodic table (39.948g).
12.4 g Ar = 12.4 (g) / 40 (g/mol) = 0.31 moleAr
molar mass of Ar being 40 g/mol (39.95 to be more precise)
0.799 mol
31.9 g Ar / 39.948 g mol-1 Ar
The atomic mass of Ar is 39.9Amount of Ar = mass of pure sample/molar mass = 11.8/39.9 = 0.296mol
There are 0.296 moles of argon in a 11.8g pure sample.
3.40 grams ÷ 39.95 grams/mole = .0851 moles
what is the amount in moles of 3.65 g Zn
.69mol
2
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
0.25 moles, approx.
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
.45mol of Mg3PO42
118g = 4.162oz
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
0.25 moles, approx.
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
Mass = Moles x Ar = 12.5 x 24 = 300g
Mol = mass/Ar (relative atomic mass)For Bromine Ar is 79.9 g/mol.Mol= 0.476/79.9 = 5.96x10-3
(6.02*10^24)*0.44 = 2.6488*10^24In 1 mol of any element there are 6.02*10^24 atoms.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
moles= mass/Mr so 525 divided by the Mr of ZnCl-2 Mr of ZnCl-2= (Ar of Zn= 65.37)+(2 x Ar of Cl= 2 x 35.5= 71) = 136.37 moles= 525/136.37 = 3.85 moles to 3 significant figures. (in grams) divide the answer by 1000 to get mg so 3.85/1000= 0.00385 moles
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles