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For this you need the Atomic Mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams
35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
Wiki User
∙ 15y ago
Wiki User
∙ 11y agomoles = weight / atomic weight = 1 g / 24.3 g mol-1 = 0.0411 moles
Wiki User
∙ 10y agoAtomic mass of Mg = 24.3
Amount of Mg = 13.2/24.3 = 0.543mol
There are 0.543 moles of magnesium in a 13.2 gram pure sample.
Wiki User
∙ 14y ago53.31g/24.305g= 2.19 moles
Wiki User
∙ 12y ago.206 mol
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What is the molarity of a solution with 120 grams of calcium nitrite in 240 mL of water?
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