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The answer is 0,253 moles.
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∙ 12y ago
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How many moles are in 100mg of citric acid?
First you need the molar mass of citric acid. It is 192 g/mol. Now you can calculate the number of moles: 0.1 g x (1 mol/192 g) = 0.00052 mol
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
How many moles of CCl4 are there in 56 g?
The answer is 0,364 moles.
How many moles is 573.28 of g of AgCI?
573,28 of g of AgCI is equivalent to 4 moles.
How many moles in a 48.5 g sample of CS2?
48,5 g sample of CS2 is the equivalent of 0,637 moles.
How many moles are in 100mg of citric acid?
First you need the molar mass of citric acid. It is 192 g/mol. Now you can calculate the number of moles: 0.1 g x (1 mol/192 g) = 0.00052 mol
How many grams of aluminum are needed to react with 192 g of oxygen gas?
First determine the balanced chemical reaction:4Al + 3O2 ---> 2Al2O3Next figure out the number of moles of oxygen you start with by dividing 192 by the molecular weight of oxygen (16 g/mol). Then use the coefficients from the reaction to determine how many moles of Al would need to react with the oxygen to convert all the oxygen and aluminum to aluminum oxide.192 g * (1 mol O / 16 g O) * (4 moles of Al/6 moles of O) = 8 mol of AlFinally multiply by the molecular weight of Aluminum to figure out the mass:8 mol Al * (27 g/mol) = 216 g of Al
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
How many moles of CCl4 are there in 56 g?
The answer is 0,364 moles.
How many moles are in 23.34 g of NaCl?
The answer is 0,4 moles.
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
How many moles is 573.28 of g of AgCI?
573,28 of g of AgCI is equivalent to 4 moles.
How many moles is 573.28 g of AgCI?
573,28 of g of AgCI is equivalent to 4 moles.
