in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g
1 mol of water is 18,01528 g.
2,00 grams of H2O have 0,11 moles.
9.9 mols?
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
The number of molecules is 2,308.10e23.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams
360 g H2O x 1 mol/18g H2O x 6.02x10^23 H2O molecules/mol x 2 H atoms/molecule = 2.4x10^25 hydrogen atoms.
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
The number of molecules is 2,308.10e23.
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
The molarity is 0,41 mol/L.
N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams
360 g H2O x 1 mol/18g H2O x 6.02x10^23 H2O molecules/mol x 2 H atoms/molecule = 2.4x10^25 hydrogen atoms.
0.8 moles HNO3 (63.018 grams/1 mole HNO3) = 50 grams nitric acid ===============
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
32.9 g / 32.0 (g/molO2) = 1.028 mol O21.028 (O2) * 2 (H2O) * 18.02 (g/mol ) = 37.1 gram H2O