.391 moles of Na in NaCL
The answer is 0,25 moles.
The atomic weight of Na is 23.0 g/molTo convert moles to grams:grams Na = 2.04 mol Na23.0 g = 46.9 g Na1 molMultiply by grams per mole. Moles cancel out.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
3 moles Na2CO3 (2moles Na/1mole Na2CO3)(22.99 grams Na/1 mole Na) = 138 grams of sodium
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.17.5 grams Na / (23.0 grams) = .761 moles Na
2.35 mol Na X (grams Na / 1 mol Na) = grams Na the element's amu on your periodic table is the amount of grams in one mole of that element.
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na Ã— (23.0 grams) = 48.3 grams Na
0.21705 moles. There are 22.9898 grams sodium in 1 mole.
None. There is no hydrogen in sodium
Mass of 2 moles of Na = 2 x atomic mass of Na = 2 x 23.0 = 46.0g
1 mole Na = 22.990g Na 10g Na = 1mol Na/22.990g Na = 0.4 mole Na
2 mol x 22.99 g Na= 45.98 g Na
Find the moles by taking the 8 grams and dividing by the molecular weight of Cu. Then multiply the moles by Na (6.02*10^23).
The atomic mass of sodium, Na is 23.0 Amount of Na = 454/23 = 19.7mol
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
1 mole Na = 22.989770g 10 moles Na = 10 x 22.989770g = 229.89770g
1.50 moles Na x 22.9 g/mole = 34.4 g (3 significant figures)
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
I must assume that this is a decomposition reaction, though you do not tell me! Balanced equation. Na3PO4 -> 3Na(+) + PO4(3-) Get moles Na ions. Molarity = moles of solute/Liters of solution (425 ml = 0.425 Liters ) 0.900 M Na(+) = mole Na(+)/0.425 Liters = 0.3825 mole Na(+) Drive against Na3PO4 0.3825 moles Na(+) (1 mole Na3PO4/3 moles Na(+))(163.94 grams/1 mole Na3PO4) = 20.9 grams sodium phosphate needed
Atomic mass of Na: 23.0 grams1.50 moles × (6.02 × 1023 atoms) = 9.03 × 1023atoms