0
to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 )
then multiply the no of moles by the molecular mass that is for mole gram conversion
so you have (23+16+1)= 40
and already you have multiplied (2.40)=80
then 2 . 40 = 120
then 80 / 40 = 2
the answer is 2
youmna zakarya
Wiki User
∙ 15y agoIt all depends how much (mL) of 5N NaOH you have...what I can tell you is that the density for 5N NaOH is 1.17 (g/cm3) = 1.17 (g/mL)...so if you have given volume of 5N NaOH, you can calculate the amount (g) of NaOH you have.
Wiki User
∙ 14y agoThis problem requires the molecular weight of the molecule (sodium hydroxide). The molecular weight can be determined by adding all the atomic masses together. Sodium's Atomic Mass is 23.0, oxygen is 16.0, and hydrogen is 1.0, for a total of 40.0 grams. For mole to gram conversions, take the number of moles and multiply it by the molecular mass.
2.00 moles NaOH
Wiki User
∙ 14y agoThis problem requires the molecular weight of the molecule (sodium hydroxide). The molecular weight can be determined by adding all the atomic masses together. Sodium's atomic mass is 23.0, oxygen is 16.0, and hydrogen is 1.0, for a total of 40.0 grams. For mole to gram conversions, take the number of moles and multiply it by the molecular mass.
2.00 moles NaOH × 40.0 grams = 80.0 grams NaOH
Wiki User
∙ 14y agoFor this you need the atomic (molecular) mass of NaOH. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NaOH=40.0 grams
5.40 moles NaOH × (40.0 grams) = 216 grams NaOH
Wiki User
∙ 14y ago200g
5 M means it has 5 moles per liter. if there are five liters then you have 5 moles. NaOH has 40 grams per mole. so 5moles x 40g/mole = 200 grams.
Wiki User
∙ 12y ago5 grams NaOH (1 mole NaOH/39.998 grams)
= 0.125 moles sodium hydroxide ( could call it 0.1 mole )
========================================
Wiki User
∙ 8y agoThis density is 1,2218 g/cm3 at 20 oC.
Wiki User
∙ 8y ago5.5 moles of NaCl weigh321,42 g.
Add your answer:
Earn +20 pts
How many moles of NaOH are in 8 g of NaOH?
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
How many grams does 2.2 moles of NaOH weigh?
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
How many moles of NaOH are in 8 g of NaOH?
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
How many grams of NaOH are there in 5.2 moles NaOH?
208g NaOH
How many moles are there in 9.4 g of NaOH?
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
How many grams does 2.2 moles of NaOH weigh?
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
How many grams of sodium hydroxide (NaOH) are there in 0.150 mol?
0,15 moles NaOH contain 6 g.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many grams of NaOH are formed from reacting 120g sodium carbonate with excess calcium hydroxide?
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
