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To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3.

2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 .

Set up a proportion.

3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3

Cross multiply and divide.

3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.

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14y ago
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13y ago

Balanced equation first. ( looks like iron III )

4Fe + 3O2 -> 2Fe2O3

I will assume iron limits

5 moles Fe (2 moles Fe2O3/4 moles Fe)

= 2.5 moles Fe3O3 made

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12y ago

7.5 moles.

There are 3 x 2.5 = 7.5 moles Fe in 2.5mole Fe3O4

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11y ago

1 mole Fe =56.85g(from Periodic Table)

(25.85g Fe)(1mole Fe/56.85g Fe)=0.44mol

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11y ago

25 grams Fe2O3 (1 mole Fe2O3/159.7 grams)

= 0.16 moles iron (III) oxide ( Ferric oxide )

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11y ago

0.25 moles iron (6.022 X 1023/1 mole Fe)

= 1.5 X 1023 atoms of iron

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Q: How many Fe atoms are in 0.25 moles of Fe?
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