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Answered 2012-03-17 12:01:29
No of moles= given mass/molecular mass = 600/30= 20 moles
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The answer is 97,66 moles.
Ethane has the formula CH3CH3. So, each mole of ethane contains 6 moles of H.13.78 moles ethane x 6 moles H/mole ethane = 82.68 moles H. If the question is asking how many moles of hydrogen GAS are needed, then the answer is 1/2 of 82.68 since hydrogen gas is H2.
124 grams of ethane is equal to 4,124 moles.
How many moles of oxygen are required to burn 22.4 liters of ethane gas C2H6 at standard conditions?
2c2h6+702=4co2+6h20 2moles of ethane :7 moles of oxygen 0.9333 of ethane:? cross multiply it and the answer will be 3.266666
Ethane contain 20 % hydrogen.
Ethane is C2H6 and combustion of ethane is 2C2H6 + 7O2 ==> 4CO2 + 6H2OThus for combustion of 2 moles of ethane, one requires 7 moles O2The mass of O2 required thus is 7 moles O2 x 32 g/mole O2 = 224 g of O2 needed
The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.
11,2 moles carbon dioxide are obtained.
600g = 21 oz (21.16437717)
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
That will depend greatly on the density of the item. 600g of flour and 600g of water will not be the same number of cups. Without knowing what you're measuring, I can't give you a precise conversion.
Since a mole is 6.022x10-23 elementary entities, then I'd say to divide 3.754x10-23 by 6.022x10-23, resulting in 0.6233 moles of ethane.
There is a total of 8 atoms in Ethane.
at STP 1 mole occupies 22.4 litres. 64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
That is 21.164 ounces.
mol. mass of ethane = 2x12.01+ 6x1.008= 30.01g/mol # of mole in 0.334 of ethane= 0.334/30.01= 0.01mol
Ethane has 65,869 Btu per gallon.
6 hydrogen atoms. formula of ethane is C2H6
It equals about 2 and 1/2 cups
That is approximately 2.7 cups.
600g is 1.3 (1.32277) pounds.
About 1.323 pounds to 600g
600g = 1.3 (1.32277) pounds.
Assuming density of 1g/ml, 0.6 litres
How many moles are there in 600g of ethane?
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