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The chemical formula for the compound calcium chloride is CaCl2.
The Atomic Mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol
There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.
Wiki User
∙ 9y ago
Wiki User
∙ 11y ago110
You surely mean CaCl2, which is calcium chloride (there is no element with the symbol Ci.) On the Periodic Table, calcium has an atomic mass of about 40, and chlorine has an atomic mass of about 35.5, and in one formula unit of calcium chloride there's one calcium for every two chlorines. So, 40+35.5+35.5 equals 111. So in one mole of calcium chloride, there's 111 grams of matter.
Wiki User
∙ 9y agoThe atomic number of the element calcium, chemical symbol Ca is 40.1Amount of Ca = mass of sample/molar mass = 21.0/40.1 = 0.524mol
There are 0.524 moles of calcium in a 21.0g pure sample.
Wiki User
∙ 15y agoFor this you will need the atomic masses of the elements involved to get a molecular mass.
C- 12.0
O2- 32.0
CO2- 44.0 grams
Then you take the number of moles and multiply it by the molecular mass. Divided by one mole for units to cancel.
0.2 mole CO2 × (44.0 grams) = 8.80 grams CO2
Wiki User
∙ 11y agomoles = 2 / 110.98 = 0.018 moles or 18 millimoles
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∙ 10y agomoles = Molarity X Volume = 0.1 L X 0.2 M = 0.02 moles
Wiki User
∙ 6y agoIf you think to atomic weight of calcium this is 40,078(4).
Wiki User
∙ 14y ago20g/40.1g=.4988 moles
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What is he longest 20 cm 20 inches 200 mm 02m?
Convert them all into the same unit, for this case let's say cm. 20cm = 20cm 20 inches = 50.8cm 200mm = 20cm When you type 02m, do you mean 2m or 0.2m? 0.2m = 20cm 2m = 200cm If 0.2m, then 20 inches is the longest length. If 2m then that is the longest length.
How many times greater is 2 cm to 7 km?
7km is 350000 times greater than 2cm. Solution: 1. Clarify the question "How many times greater is 7km than 2cm?" 2. Convert both units into meters: 7*1000=7000m, 2*1/100=.02m 3. Divide the big number by the small number: 7000 / .02 = 350000 ====== Answer 1: 100 cm in a m, 1000 m in a km. 3.5 2 in 7. 3.5 * 100*1000 = 350000 centi-meters = 10**-2 meters kilo-meteres = 10**3 meters 2cm < 7km 2*10**-2/7*10**3 = (2/7)*10**-5
How much force is required to pump 1900 liters of water per minute through 20 mm nozzle to spray 50m in distance?
V= Q/A (velocity = volumetric flow rate / area) conversion: 1000L = 1m3; therefore 1900L/min= 1.9m3/min V = (1.9m3/min * 1min/60s) / Pi*(.02m)2/4 = 100.798 m/s Simplified Bernoulli Equation: ∆P/rho + 0.5*(initial velocity2-final velocity2) = 0 (rho=density) (equation assumes no fluid height changes and no frictional losses) ∆P/(1000 kg/m3) + 0.5*(02 - (100.798 m/s)2) = 0 ∆P = 5.08x106 N/m2= 5.08x106 Pascals P= F/A (Pressure= Force/Area) F= P*A F= ∆P * Area = 5.08x106 * Pi*(.02m)2/4 = 1595.97N A height of nozzle was not given; however, there is a minimum height when you specify a horizontal distance of 50m. Minimum nozzle height above ground to reach 50 meters horizontal distance: d=r*t (distance= rate * time) t= d / r t= 50m / 100.798m/s = 0.496s (time for a droplet to leave the nozzle and travel 50m horizontally) h= g*t2 (height of a falling object = gravity * time2 assuming spray nozzle is horizontal) h= 9.81m/s2 * (0.496s)2 = 2.41m above grade The minimum height will change if the nozzle is angled up or down. Note: 9.81m/s2 is approximately the earth's gravitational acceleration at sea level at the equator.
