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74.168 u NH3
Determine relative mass of NH3 molecule: (1 x 14.007 u N) + (3 x 1.008 u H) = 42.357 u
Multiply the number of molecules of NH3 by its relative molecular mass.
1.751024 molecules NH3 x (42.357 u NH3)/(1 molecule NH3) = 74.168 u NH3
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What is the mass in grams of 1.20x1025 molecules of ammonia NH3?
The mass of ammonia is 339,7 g.
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
What pair of molecules has the strongest dipole - dipole interactions co2-co2 or co2-ch4 or nh3-nh3 or nh3-ch4 or ch4-ch4.?
nh3-nh3 because they are both polar molecules
How many moles are in 7.95E22 molecules of NH3?
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
What is the mass in grams of 1.20x1025 molecules of ammonia NH3?
The mass of ammonia is 339,7 g.
How many grams are their in 3.4x10molecules of NH3?
The mass is 9,6.10e-22 g for 34 molecules.
How many atoms are there in 0.850 mol of ammonia?
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024
How do you calculate the mass in grams of 4.2 x 1025 NH3?
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
What pair of molecules has the strongest dipole - dipole interactions co2-co2 or co2-ch4 or nh3-nh3 or nh3-ch4 or ch4-ch4.?
nh3-nh3 because they are both polar molecules
Is NH3 soluble in CCl4?
it will not dissolve NH3 in poler molecules
How many molecules of ammonia are contained in 10 moles of ammonia NH3?
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
What represents a molecules?
NH3
How many moles are in 7.95E22 molecules of NH3?
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
