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Since a mole is 6.022x10-23 elementary entities, then I'd say to divide 3.754x10-23 by 6.022x10-23, resulting in 0.6233 moles of ethane.

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0The molar mass of C2H6 is 30 {(12*2)+(1*6)}. The number of moles(n)=mass/molar mass n=9.3 g/ 30 g mol-1 =0.31 mol. The number of molecules of C2H6 =n* Avogadro number(L)= 0.31*6.022*1023= 1.86682*1023 The no. of atoms in one mole of C2H6=8 The no. of atoms in 0.31 moles of C2H6=8*1.86682*1023 =14.93456*1023 =1.49*1024

If you meant 1.5*10^23 and not 1.51023 molecules, see below:1.5*10^23 molecules / (6.022*10^23 molecules/mol)= 1.5/6.022 mol=.25 moles, rounded to two significant figures.

One mole C2H6 has 2 moles of carbon and 6 moles of hydrogen.

Balanced equation first. 2C2H6 + 7O2 -> 4CO2 +6H2O I suspect C2H6 of limiting the reaction. 2 moles C2H6 (1.6 moles O2/2 moles C2H6) = 1.6 moles O2 left over and all of the C2H6 is consumed.

The answer is 2,17 moles carbon.

The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6

Quite a few! 6.75 moles C2H6 (6.022 X 10^23/1 mole C2H6) = 4.06 X 10^24 atoms

The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25

For this you need the atomic (molecular) mass of C2H6. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H6= 30.1 grams80.0 grams C2H6 / (30.1 grams) = 2.66 moles C2H6

124 grams of ethane is equal to 4,124 moles.

The formula C2H6 shows that there are two carbon atoms in each molecule of the compound. Since the formula mass for elemental carbon is a single atom, 500 moles of the compound will contain 1000 moles of carbon.

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Ethane contain 20 % hydrogen.

more moles than a creepy guys face

The answer is 1 mol carbon.

First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.

Chlorocthase C2H2Cl Ethanec C2H6 Chloroethane, C2H5Cl Ethane, C2H6

They are all the same.

at STP 1 mole occupies 22.4 litres. 64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules

7/2O2+C2H6->2CO2+3H2O Mole ratio of C2H6:CO2=1:2 No.of mole of CO2=2mol

The number of molecules in 15 g ethane is approx. 3,011.10e23.

Okay, 1 mole of any substance contains 6.02x1023 representative particles. So, if you have a mole of C2H6 (ethane), you have Avogadro's number of molecules. You're asking about atoms, so if you look at the formula for ethane, you see 2 carbons and 6 hydrogens for a total of 8 atoms per molecule. Multiply Avogadro by 8 to get the total number of atoms. Then multiply by the given number of moles.6.02x1023 x 8 (#of atoms) x 5.6 (number of moles) = 269.7x1023 = approximately 2.7x1025 atoms.

350 g C2H6 x 1 mole C2H6/30 g x 2 moles C/mole C2H6 x 12 g/mole C = 280 g carbonDone another way: %C = 24/30 (x100%) = 80% 0.8 x 350 g = 280 grams carbon

No, C2H6 is an alkane.

The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.

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