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That depends on the oxidation state of the Fe.

Fe(II) or Fe(III)

Fe + Cl2 --> FeCl2 Fe(II)

Answer: 4.4 mol chlorine. The iron(II)chloride is normally prepared using hydrochloric acid rather than chlorine.

Fe + 1.5 Cl2 --> FeCl3

Answer: 6.6 mol

The iron(III)chloride is could be prepared using hot granulated iron in chlorine.

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12y ago
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13y ago

First write the balanced equation to find the molar ratio :

4Fe3O4 + O2 --> 6Fe2O3

Fe3O4/Fe2O3 = 4 : 6 = 2 : 3 = (2/3) : 1

Then recalculate (transform) this to 4.47 moles Fe2O3

Fe3O4 : Fe2O3 = (2/3) : 1

= 4.74 * [(2/3) : 1 ]

= (2/3)*4.74 : 4.74

= 3.16 : 4.74

So the answer is that 4.74 moles Fe2O3 are prepared from 3.16 moles Fe3O4

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11y ago

1.5 mole,

because 4.5 moles CO need 4.5 moles O atoms from

[ 4.5 (mole O) / 3 (mole O/mole Fe2O3) ] = 4.5/3 = 1.5 mole Fe2O3 to become 4.5 moles CO2

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13y ago

3 molecules for iron III oxide

4Fe + 3O2 --> 2Fe2O3

2 molecules for iron II oxide

4Fe + 2O2 --> 4FeO

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11y ago

1 mole of Cl2. Assuming

Fe + Cl2 -> FeCl2

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11y ago

3FeO+2Al→Al2O3+3Fe

3.2 moles Al.

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4y ago

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Q: How many moles of Cl are in one mole of FeCl2?
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