26,3 g cobalt is equivalent to 0,446 moles.
For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.5 grams / 28.0 grams = .161 moles CO
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
382 g Co contain 6,482 moles.
1,4 moles carbon monoxide are produced.
0,83moles glucose are burned.
2,55 moles of the compound CO have 71,4 grams.
For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.5 grams / 28.0 grams = .161 moles CO
The atomic weight of Cr is 52.0 g/mol1. Convert grams of Cr to moles of Cr:moles Cr = 45.6 g Cr1 mol = 0.877mol Cr52.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of Co is 58.9 g/mol2. To convert 0.877 moles of Co to grams of Co:grams Co = 0.877 mol Co58.9 g = 51.7 g Co1 molMultiply by grams per mole. Moles cancel out.Note that since the atomic weight of Co is larger than the atomic weight of Cr, the mass of the same number of moles is also larger.
1,4 moles of CO are produced.
4,54 L of CO have 0,182 moles.
How many moles of atoms are contained in 382 g Co
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
The answer is 6,482 moles.
382 g Co contain 6,482 moles.
no
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================