6,49 moles of water are obtained.
It forms H2O when burned.There are 3.744 moles of H2O after burned.
9
how many moles are in 95.0 gram of octane?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
It forms H2O when burned.There are 3.744 moles of H2O after burned.
9
30 moles
how many moles are in 95.0 gram of octane?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
11,2 moles carbon dioxide are obtained.
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
The formula for normal octane is C8H10. Each mole burned creates 8 moles of CO2. A mole of octane is 106 grams, 8 moles of CO2 is 8x44 = 352 grams So 1.8 kg of octane would produce 1.8x(352/106) = 5.98 g CO2. As the octane value is given to 1 decimal place the answer can be no more accurate so 6.0 kg.
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
6 moles COULD be produced
1,4 moles of CO are produced.