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6,49 moles of water are obtained.

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Q: How many moles of H2O are produced when 0.721mol of octane is burned?
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How many moles of H2O are produced when 0.468 mol of octane is burned?

It forms H2O when burned.There are 3.744 moles of H2O after burned.


How many moles of water will be produced from 1 mole of octane?

9


How many moles of carbon dioxide are produced when 10.0 moles of propane are burned in excess oxygen on gas grill?

30 moles


How many moles are in 95.0 gram of octane?

how many moles are in 95.0 gram of octane?


How many moles of water can be produced by burning 325g of octane in excess oxygen?

Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O


How many moles of CO2 are produced when 5.60 mol of ethane are burned in an excess of oxygen?

11,2 moles carbon dioxide are obtained.


How many moles of are present in 16.0 of octane?

C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane


How much co2 is formed from the burning of 1.8 kg of octane?

The formula for normal octane is C8H10. Each mole burned creates 8 moles of CO2. A mole of octane is 106 grams, 8 moles of CO2 is 8x44 = 352 grams So 1.8 kg of octane would produce 1.8x(352/106) = 5.98 g CO2. As the octane value is given to 1 decimal place the answer can be no more accurate so 6.0 kg.


How many moles of carbon dioxide are produced when 84.4 moles of hexane is burned?

Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2


What weight of water is produced burning 19.8grams of octane?

The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water


How many moles of water vapor can be produced from 2 moles of ammonia?

6 moles COULD be produced


How many moles of CO are produced when 1.4 moles C reacts?

1,4 moles of CO are produced.