answersLogoWhite

0


Best Answer

This reaction is:
2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2
From 4 moles of Al 6 moles of hydrogen are obtained.

User Avatar

Wiki User

βˆ™ 7y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles of H2 can you get from 4 moles of Al?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Natural Sciences

How many H2O can you get from 4 moles of H2 and unlimited O2?

4 moles also 2 moles of oxygen will be consumed


What is the mass of hydrogen gas released from 3.70 g of aluminum metal and hydrochloric acid 2 Al(s) plus 6 HCl(aq) 2 AlCl3(aq) plus 3 H2(g)?

1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2


How many moles of NH3 can be produced from 2.37x10-4 moles of H2?

First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas


What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?

Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================


How many moles of Na are needed to make 4 moles of H2?

It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written

Related questions

How many H2O can you get from 4 moles of H2 and unlimited O2?

4 moles also 2 moles of oxygen will be consumed


What is the mass of hydrogen gas released from 3.70 g of aluminum metal and hydrochloric acid 2 Al(s) plus 6 HCl(aq) 2 AlCl3(aq) plus 3 H2(g)?

1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2


How many moles of O2 must react with 5 moles of Al?

Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction. 2Al + 6HCl --> 2AlCl3 + 3H2 3.0 moles Al (3 moles H2/2 moles Al) = 4.5 mole hydrogen gas produced =========================


How many moles of NH3 can be produced from 2.37x10-4 moles of H2?

First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas


What is the mass of 4 moles of hydrogen molecules (H2)?

8.086g


What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?

Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================


How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2 Reaction N2(g) plus 3 H2(g) 2 NH3(g)?

2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O


How many moles of Na are needed to make 4 moles of H2?

It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written


How many moles of aluminum oxide can be made if 4.0 moles Al completely react?

The balanced chemical equation for the reaction between aluminum (Al) and oxygen (Oβ‚‚) to form aluminum oxide (Alβ‚‚O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Alβ‚‚O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.


How many moles of aluminum oxide will be produced from 8 moles of Al?

depends on how much aluminum oxide you have, 1gram, 2 billion Kg? how many? cant find the number of moles of oxygen without knowing the mass of the al203


When 4 moles of aluminum are allowed to react with an excess of chlorine gas how many moles of aluminum chloride are produced?

Four:2 Al + 3 Cl2 --> 2 AlCl3so: 4 Al + 6 Cl2 --> 4 AlCl3


How many moles of copper will react with 4 moles of sulfuric acid?

4. The chemical equation is Cu + H2SO4 → CuSO4 + H2. Copper and sulfuric acid have the same coefficient (1), so the same number of moles of copper and sulfuric acid are used.