answersLogoWhite

Top Answer
User Avatar
Wiki User
Answered 2009-10-30 15:39:00

volume given =27.5ml
molarity of base=0.105
find number of moles=
moles=vol(cm3)/1000*molarity of NaCl
moles=27.5/1000*0.105
=3.82 moles of sodium chloride

001
๐Ÿ™
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
๐Ÿ˜‚
0
User Avatar

Your Answer

Related Questions


Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============


Molarity = moles of solute/Liters of solition (300 ml = 0.300 Liters ) 0.40 M NaCl = moles NaCl/0.300 Liters = 0.120 moles NaCl



Molarity = moles of solute/Liters of solution 3.45 M NaCl = moles NaCl/5 liters = 17.25 moles


moles of NaCl in the solution = mass of dissolved NaCl/58,44


By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.


Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl )


Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------


Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------


Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles


Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============


Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========


Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------


Molarity = moles of solute/volume of solution so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl) = 2.1389 moles NaCl/400 Liters = 0.00535 M NaCl


Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------


Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------


I assume you mean 174 grams NaCl. Be careful with units, decimal points and amounts as we are not mind readers here and I could be wrong about this assumption. Regardless, need moles NaCl first.174 grams NaCl (1 mole NaCl/58.44 grams)= 2.977 moles NaCl=================now,Molarity = moles of solute/Liters of solutionMolarity = 2.977 moles NaCl/4.00 Liters= 0.744 M NaCl solution-------------------------------


Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------


Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------


.100M solution x.200L solution = .02 moles NaCl .02 moles x 58.44g NaCl = 1.1 g NaCl with correct amound of significant figures ---- 1 mol Nacl


0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)


Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )



In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.


Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------



Copyright ยฉ 2021 Multiply Media, LLC. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.