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Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of Solution

Volume of Solution required = 5.00L

We can say therefore that:

Number of Moles of NaOH needed to prepare the solution

= Concentration of NaOH * Volume of Solution required

Therefore:

Number of Moles of NaOH needed to prepare the solution

= 0.025M * 5.00L

= 0.125moles

From this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.

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11y ago
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8y ago

The total number of moles of solute in 2.0 liters of 5.0 M NaOH is 10 moles NaOH.

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12y ago

1mol

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8y ago

Only one mole KNO3

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11y ago

10

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Q: How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
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