Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
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How many moles of C are needed to react with 0.490 mole SO2?
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1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
The maximal mass is 30 moles sulfur dioxide.
How many moles of C are needed to react with 0.490 mole SO2?
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The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
1.75 moles SO2 x 6.02x10^23 molecules SO2/mole SO2 = 1.05x10^24 molecules
1 mole SO2 = 64.064g SO2 0.45g SO2 x 1mol SO2/64.064g SO2 = 0.0070 mole SO2
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Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
The maximal mass is 30 moles sulfur dioxide.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Cock and booty ball
.75 moles times 64 grams/mols = 48 grams
Since oxygen is diatomic it requires 2 moles of oxygen.