answersLogoWhite

0


Best Answer

2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.

User Avatar

Wiki User

7y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles of bromine atoms are in 2.60x102 grams of bromine?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many atoms are in 10.0 moles of bromine atoms?

10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.


How many moles of bromine are in 2.60100 grams of bromine?

.0326 moles


How many moles of bromine atoms in 1 mole of bromine gas Please show equation?

Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.


How many moles of bromine gas are in 37.7 grams?

.467 mol of Bromine gas


What is the mass in grams of 0.37 moles of bromine?

29,56448 (rounded 29,56) grams


How to convert grams to atoms?

To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.


How many atoms of bromine will you multiply to get moles of bromine?

One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.


How many grams are in 2.9 moles of Br2?

2,9 moles of bromine is equivalent to 463,4432 g.


How many atoms are in 1.54 moles of Bromine Br?

If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.


How many moles on 738 grams or iron and how many atoms?

738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms


How many moles of bromine will be formed upon the complete reaction of 0.196 moles bromine trifluoride?

The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.


Aluminum will react with bromine to form aluminum bromide Al2Br6 What mass of bromine g is needed to form 1.42 mol of Al2Br6?

The gram formula unit or molar mass for aluminum bromide is 533.38.* Therefore, 1.42 moles has a mass of 757.4 grams. The mass of 6 moles of bromine atoms is 479.42. Therefore, the mass fraction of bromine in aluminum bromide is 479.42/757.4 or 0.633, and the mass in grams of bromine required to form 1.42 moles of aluminum bromide is 0.633 X 757.4 or 479 grams, to the justified number of significant digits (limited by the precision given for the number of moles.) ___________________ *This is equal to the sum of (2 times the gram atomic mass of aluminum) and (6 times the gram atomic mass of bromine).